Luhn algorithm

The algorithm is in the public domain and is in wide use today. It is not intended to be a cryptographically secure hash function; it protects against random error, not malicious attack. Most credit cards and many government identification numbers use the algorithm as a simple method of distinguishing valid numbers from collections of random digits.

Informal explanation

The formula generates a check digit, which is usually appended to a partial account number to generate the full account number. This account number must pass the following algorithm (and the check digit chosen and placed so that the full account number will):

1. Starting with the second to last digit and moving left, double the value of all the alternating digits. For any digits that thus become 10 or more, add their digits together. For example, 1111 becomes 2121, while 8763 becomes 7733 (from (1+6)7(1+2)3).
2. Add all these digits together. For example, 1111 becomes 2121, then 2+1+2+1 is 6; while 8763 becomes 7733, then 7+7+3+3 is 20.
3. If the total ends in 0 (put another way, if the total modulus 10 is 0), then the number is valid according to the LUHN formula, else it is not valid. So, 1111 is not valid (as shown above, it comes out to 6), while 8763 is valid (as shown above, it comes out to 20).

Algorithm

The algorithm proceeds in three steps. Firstly, every second digit, beginning with the next-to-rightmost and proceeding to the left, is doubled. If that result is greater than nine, its digits are summed (which is equivalent, for any number in the range 10 though 18, of subtracting 9 from it). Thus, a 2 becomes 4 and a 7 becomes 5. Secondly, all the digits are summed. Finally, the result is divided by 10. If the remainder is zero, the original number is valid.

function checkLuhn(string purportedCC) {
int sum := 0
int nDigits := length(puportedCC)
int parity := nDigits modulus 2
for i from 0 to nDigits - 1 {
int digit := integer(purportedCC[i])
if i modulus 2 = parity
digit := digit × 2
if digit > 9
digit := digit - 9
sum := sum + digit
}
return (sum modulus 10) = 0
}

Example

Consider the example identification number 456-565-654. The first step is to double every other digit, starting with the second-to-last digit and moving left, and sum the digits in the result. The following table shows this step (highlighted rows indicating doubled digits):

The sum of 30 is divided by 10; the remainder is 0, so the number is valid.

External link

• C# implementation -- This code is also broken. Does not seem to compile with Mono.
• Java implementation - this code is broken. Method is void and returns a boolean?
• JavaScript implementation
• Python implementation